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Example 1.16
1.   
Solve the following logarithms (numbers
greater than 10). a. log 53.2          1 b. log 234,000
2.   
Solve the following logarithms (numbers
between 0 and 1). a. log 0.532       b. log 0.00532
Answer :
1.       a. log
53.2 = log (5.32 x 10')                                   b. log
234,000 = log (2.34 x 105)
= log 5.32 + log 10'                                         = log 2.34 + log 105
= 0.726 + 1                                                    =
0.369 + 5
= 1.726                                              =
5.369
2.    a. log
0.532                           =
log 5.32 x 10' = log 5.32 – 1
= 0.726 – 1 = –0.274 
b. log 0.00532 = log 5.32 x 10-3 = log
5.32 – 3 = 0.726 – 3 = –2.274
5. Determining
Antilogarithm of a Number
 After learning about the
ways to determine the logarithm of a number, now you will be introduced to the
concept of the antilogarithm ofa number, which is an inverse of the logarithm.
Determining the antilogarithm ofa number means finding a number which is given
its logarithm value using antilogarithm table. To determine antilogarithm of a
number, study the following examples.
Table 1.2 Antilogarithm Table
| 
   
X 
 | 
  
   
0 
 | 
  
   
1 
 | 
  
   
2 
 | 
  
   
3 
 | 
  
   
4 
 | 
  
   
5 
 | 
  
   
6 
 | 
  
   
7 
 | 
  
   
8 
 | 
  
   
9 
 | 
 
| 
   
00 
 | 
  
   
100 
 | 
  
   
100 
 | 
  
   
101 
 | 
  
   
101 
 | 
  
   
100 
 | 
  
   
101 
 | 
  
   
101 
 | 
  
   
102 
 | 
  
   
102 
 | 
  
   
102 
 | 
 
| 
   
01 
 | 
  
   
102 
 | 
  
   
103 
 | 
  
   
103 
 | 
  
   
103 
 | 
  
   
103 
 | 
  
   
104 
 | 
  
   
104 
 | 
  
   
104 
 | 
  
   
104 
 | 
  
   
104 
 | 
 
| 
   
02 
 | 
  
   
105 
 | 
  
   
105 
 | 
  
   
105 
 | 
  
   
105 
 | 
  
   
106 
 | 
  
   
106 
 | 
  
   
106 
 | 
  
   
106 
 | 
  
   
107 
 | 
  
   
107 
 | 
 
| 
   
03 
 | 
  
   
107 
 | 
  
   
107 
 | 
  
   
108 
 | 
  
   
108 
 | 
  
   
108 
 | 
  
   
108 
 | 
  
   
109 
 | 
  
   
109 
 | 
  
   
109 
 | 
  
   
109 
 | 
 
| 
   
04 
 | 
  
   
110 
 | 
  
   
110 
 | 
  
   
110 
 | 
  
   
110 
 | 
  
   
111 
 | 
  
   
111 
 | 
  
   
111 
 | 
  
   
111 
 | 
  
   
112 
 | 
  
   
112 
 | 
 
| 
   
05 
 | 
  
   
112 
 | 
  
   
112 
 | 
  
   
113 
 | 
  
   
113 
 | 
  
   
113 
 | 
  
   
114 
 | 
  
   
114 
 | 
  
   
114 
 | 
  
   
114 
 | 
  
   
115 
 | 
 
| 
   
06 
 | 
  
   
115 
 | 
  
   
115 
 | 
  
   
115 
 | 
  
   
116 
 | 
  
   
116 
 | 
  
   
116 
 | 
  
   
116 
 | 
  
   
117 
 | 
  
   
117 
 | 
  
   
117 
 | 
 
| 
   
07 
 | 
  
   
117 
 | 
  
   
118 
 | 
  
   
118 
 | 
  
   
118 
 | 
  
   
119 
 | 
  
   
119 
 | 
  
   
119 
 | 
  
   
119 
 | 
  
   
120 
 | 
  
   
120 
 | 
 
| 
   
08 
 | 
  
   
120 
 | 
  
   
121 
 | 
  
   
121 
 | 
  
   
121 
 | 
  
   
121 
 | 
  
   
122 
 | 
  
   
122 
 | 
  
   
122 
 | 
  
   
122 
 | 
  
   
123 
 | 
 
| 
   
09 
 | 
  
   
123 
 | 
  
   
123 
 | 
  
   
124 
 | 
  
   
124 
 | 
  
   
124 
 | 
  
   
124 
 | 
  
   
125 
 | 
  
   
125 
 | 
  
   
125 
 | 
  
   
126 
 | 
 
| 
   
10 
 | 
  
   
126 
 | 
  
   
126 
 | 
  
   
126 
 | 
  
   
127 
 | 
  
   
127 
 | 
  
   
127 
 | 
  
   
128 
 | 
  
   
128 
 | 
  
   
128 
 | 
  
   
129 
 | 
 
| 
   
11 
 | 
  
   
129 
 | 
  
   
, 129 
 | 
  
   
129 
 | 
  
   
130 
 | 
  
   
130 
 | 
  
   
130 
 | 
  
   
131 
 | 
  
   
131 
 | 
  
   
131 
 | 
  
   
132 
 | 
 
| 
   
12 
 | 
  
   
132 
 | 
  
   
132 
 | 
  
   
132 
 | 
  
   
133 
 | 
  
   
133 
 | 
  
   
133 
 | 
  
   
134 
 | 
  
   
134 
 | 
  
   
134 
 | 
  
   
135 
 | 
 
Determine the numbers which satisfy the
following logarithms! a. 0.125                         b.
1.412
Answers:
a. Antilog
0.125 = 1.33
From the antilogarithm table, find the
two first decimals in the most left column (column x), that is 12, then
draw a line horizontally from that number to the right until intersect the
column' which
indicates number 5, so you obtain 133.
Because the integer
(characteristic) is 0, thus the antilog 0.125 = 1.33
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